U.S. presidential election, 1940 |
| Presidential Candidate |
Electoral Vote |
Popular Vote |
Pct |
Party |
Running Mate
(Electoral Votes) |
| Franklin Delano Roosevelt of New York (W) |
449 |
27,244,160 |
54.8 |
Democrat |
Henry Agard Wallace of Iowa (449) |
| Wendell Lewis Wilkie of New York |
82 |
22,305,198 |
44.8 |
Republican |
Charles L. McNary
of Oregon (82) |
| Norman Thomas of New
York |
0 |
116,410 |
0.2 |
Socialist |
Maynard C. Krueger of Illinois |
| Total |
|
49,752,978 |
100.0% |
|
| Other elections: 1928, 1932, 1936, 1940, 1944, 1948, 1952 |
| Source: U.S. Office of the Federal Register
|
Wendell Wilkie, a former Democrat, switched to the Republican party in 1939 in opposition to incumbant president Franklin
D. Roosevelt's New Deal. Wilkie campaigned against the New Deal and the
government's lack of military preparedness. During the election, Roosevelt preempted the military issue by expanding military
contracts. Wilkie then reversed his approach and accused Roosevelt of warmongering. On election day Roosevelt received 27 million
votes to Wilkie's 22 million, and in the Electoral College, Roosevelt defeated Wilkie 449 to 82.
The election was held on November 5, 1940.
See also: President of the United
States, U.S. presidential election,
1940, History of the United States (1918-1945)
|