U.S. presidential election, 1928

Presidential Candidate	Electoral Vote	Popular Vote	Pct	Party	Running Mate (Electoral Votes)
Herbert Clark Hoover of California (W)	444	21,391,381	58.2	Republican	Charles Curtis of Kansas (444)
Alfred Emmanuel Smith of New York	87	15,016,443	40.9	Democrat	Joseph Taylor Robinson of Arkansas (87)
Others including Norman Thomas	0	337,115	0.9
Total		36,744,939	100.0%
Other elections: 1916, 1920, 1924, 1928, 1932, 1936, 1940
Source: U.S. Office of the Federal Register

The campaign

The Republican Convention was held in Kansas City, Missouri from 12 June to 15 June, where Hoover became the party's candidate on the first ballot. In his acceptance speech he said "We in America today are nearer to the final triumph over poverty than ever before in the history of this land... We shall soon with the help of God be in sight of the day when poverty will be banished from this land."

The Democratic Convention was held in Houston, Texas, 26 June to 28 June. Al Smith became the candidate on the second ballot.

Although Smith did not openly come out against Prohibition, he was perceived by many as soft in the war against alcohol. The Prohibition Party threw its support to Hoover.

The Election

The election was held on November 6, 1928.

Republican candidate Herbert Hoover won election by a wide margin on pledges to continue the economic boom of the Coolidge years. Smith won the electorial votes only of the traditionally Democratic US South and a few New England States, by a narrow margin failing to even carry his home state of New York.

Socialist Party of America candidate Norman Thomas received 265,583 popular votes (0.7%).