Maxwell-Boltzmann distribution |
The Maxwell-Boltzmann distribution is a probability distribution with applications in physics and chemistry. It forms the basis of the
kinetic theory of gases, which explains many
fundamental gas properties, including pressure and diffusion. The Maxwell-Boltzmann distribution is also applied in electron
transport and other phenomena.
The Maxwell-Boltzmann distribution can be derived using statistical mechanics (see the derivation of the partition function). It corresponds to the most probable energy
distribution, in a collisionally-dominated system consisting of a large number of non-interacting particles. Since interactions
between the molecules in a gas are generally quite small, the Maxwell-Boltzmann distribution provides a very good approximation
of the conditions in a gas.
In many other cases, however, the condition of elastic
collisions dominating all other processes is not even approximately fulfilled. That is true, for instance, for the physics of
the ionosphere and space plasmas
where recombination and collisional excitation (i.e. radiative processes) are of far greater importance: in particular for the
electrons. Not only would the assumption of a Maxwell distribution yield quantitatively wrong results, but even prevent a correct
qualitative understanding of the physics involved.
The Maxwell-Boltzmann distribution can be expressed as:
-
where Ni is the number of molecules at equilibrium temperature T, having energy level Ei, N is the total
number of molecules in the system and k is the Boltzmann
constant. Essentially Equation 1 provides a means for calculating the fraction of molecules (Ni/N) that have
energy Ei at a given temperature, T. Because velocity and speed are related to energy, Equation 1 can be used to
derive relationships between temperature and the speeds of molecules in a gas.
Maxwell-Boltzmann velocity distribution
For the case of an "ideal gas" consisting of non-interacting atoms in the ground state, all energy is in the form of kinetic
energy. From the particle in a box problem in quantum mechanics we know that the energy levels for a gas in a
rectangular box with sides of lengths ax, ay, az are given by:
- (2)
where, nx, ny, and nz are the quantum numbers for x,y, and z motion, respectively. However,
for a macroscopic sized box, the energy levels are very closely spaced, so the energy levels can be considered continuous and we
can replace the sum with an integral. Furthermore, we can recognize that
(h2ni2/4ai2) corresponds to the square of the ith component of momentum,
pi2 giving:
- (3)
where q corresponds to the denominator in Equation 1. This distribution of Ni/N is proportional to the probability distribution function fp for finding a molecule with these
values of momentum components, so:
- (4)
The constant of proportionality, c, can be determined by recognizing that the probability of a molecule having any
momentum must be 1. Therefore the integral of equation 4 over all px, py, and pz must be 1.
It can be shown that:
- (5)
so in order for the integral of equation 4 to be 1,
- (6)
Substituting Equation 6 into Equation 4 and using pi=mvi for each component of momentum gives:
- (7)
Finally recognizing that the velocity probability distribution, fv is proportional to the momentum probability
distribution function as
- fv = m3fp
we get:
- (8)
Which is the Maxwell-Boltzmann velocity distribution.
Velocity distribution in one direction
For the case of a single direction Equation 8 can be reduced to:
- (9)
This distribution has the form of a Gaussian error curve. As expected for a gas at rest, the average velocity in any
particular direction is zero.
Distribution of speeds
Usually, we are more interested in the speed of molecules rather than the component velocities, where speed, v is defined such
that:
- (10)
The corresponding speed distribution is:
- (11)
Average speed
Although Equation 11 gives the distribution of speeds or in other words the fraction of molecules having a particular speed,
we are often more interested in quantities such as the average speed of the particles rather than the actual distribution. In the
following subsections we will define and derive the most probable speed, the mean speed and the
root-mean-square speed.
Most probable speed
The most probable speed, vp, is the speed most likely to be possessed by any molecule in the
system and corresponds to the maximum value or mode of F(v). To find it, we calculate
dF/dv, set it to zero and solve for v:
-
(12)
- (13)
Mean speed
The mean speed, <v>, or average speed can be calculated using the expression:
- (14)
Substituting in Equation 11 and performing the integration gives:
- (15)
Note that <v> and vp differ by a constant factor (4/π)1/2.
Root-mean-square speed
The root mean square speed, vrms is given by
- (16)
Substituting for F(v) and performing the integration, we get
- (17)
Thus,
-
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